1.

Find the nature of the roots of the quadratic equation 4x2 +43x +3 0

Answer»

We know that, D = b^2 - 4 * a * c

Then, For equation 4x^2 + 4sqrt(3)x + 3 D = (4sqrt3)^2 - 4 * 4 * 3

= 16 * 3 - 48

= 48 - 48

= 0

So, given quadratic equation has equal real roots.

the give equation has equal roots.



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