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Find the nature of the roots of the quadratic equation 4x2 +43x +3 0 |
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Answer» We know that, D = b^2 - 4 * a * c Then, For equation 4x^2 + 4sqrt(3)x + 3 D = (4sqrt3)^2 - 4 * 4 * 3 = 16 * 3 - 48 = 48 - 48 = 0 So, given quadratic equation has equal real roots. the give equation has equal roots. |
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