1.

Find the multiplicative inverse of (root 5+3i/3+root 5i)

Answer»

√5+3i/3+√5i=3+√5i/√5+3i
now RATIONALISING, we GET
(3+√5i/√5+3i)*(√5-3i/√5-3i)
=(3+√5i*√5-3i) /(√5+3i*√5-3i)
=3√5-9i+5i-3√5i^2)/(5-9i^2)
=(3√5-4i+3√5)/5+9
= -4i/14
= -2i/7 ANSWER


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