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Find the moment of force of 20 Newton about an axis of rotation at distance of 0.5 metre from the force |
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Answer» Answer:10 Nm Explanation:We know that , moment of force or TORQUE is EQUALS to the product of force applied with with the DISTANCE from the line of action of the force. Then, Force=20Newton(N) Distance=0.5meter(m) Torque=Force*Distance =20*0.5 =10Nm(ANS) |
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