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Find the minimum value of 4x2+1/x |
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Answer» For a general quadratic EQUATION AX +bx+c=0,wherea>0theminimumvalueofexpressionoccursat 4a −D
∴4x 2 +2x+1 minimumvalue= 4.4 −(2 2 −4.4.1)
= 16 12 = 4 3 Step-by-step EXPLANATION: Please mark me Brailient |
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