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Find the median of the following frequency distribution: |
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Answer» Convers given less than frequency table into normal frequency table:
n = \(\sum\)fi = 115 \(\because\) n/2 = 11/2 = 57.5 \(\therefore\) Median class = 40 - 50 l = lower limit of median class = 40 c = cumulative frequency processing class of median class = 50 f = frequency of median class = 20 h = class - interval = 60 - 50 = 10 \(\therefore\) Median = l +\(\cfrac{\frac n2-c}f\times h\) = 40 + \(\frac{57.5-50}{20}\times10\) = 40 + 3.75 = 43.75 Hence, median of marks of students is 43.75. |
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