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Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle. |
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Answer» Given, Let the smallest angle = x∘ Than the other angle = (2x – 24)° So, x∘+x∘+2x – 24 + 2x – 24 = 360∘ 6x = 360 + 48 = 408 x = \(\frac{408^∘}{6}\) = 68∘ Other angles = 2x – 24 = 2×68 – 24 = 136-24 = 112∘ Angles are = 68∘, 68∘, 112∘, 112∘ |
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