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Find the maximum or minimum value, if any, without using derivatives, of the function: –(x – 3)2 + 9 |
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Answer» It is given that f (x) = – (x – 3)2 + 9 Here (x – 3)2 ≥ 0 We can write it as – (x – 3)2 ≤ 0 By adding 9 on both sides – (x – 3)2 + 9 ≤ 0 + 9 Where f (x) ≤ 9 So the maximum value of f (x) = 9 which occurs at x = 3 which is the point of absolute maxima and minimum value does not exist. |
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