1.

Find the maximum height reached by a particle which is thrown vertically upwards with the velocity of `20 m//s` (take `g= 10 m//s^(2)`).A. 40 mB. 10 mC. 20 mD. zero

Answer» Correct Answer - C
`H=(u^(2))/(2g)=((20)^(2))/(2 xx 10)=20 m`.


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