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Find the maximum and minimum y=x^3-6x^2+9x+15 Using differentiation. |
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Answer» we have to find the derivatives of y using differentiationFor MAXIMUM and MinimumSolving the EQN, we get:We know that(dy/dx) is negative at maximum(dy/dx) is POSITIVE at minimumHere, we have both positive values. So we can further differentiate dy/dxPutting values of x ☞ 6(1) - 12 = - 6 (Maximum) ☞ 6(3) - 12 = 6 (Minimum) ∴ y is maximum at (-6) and minimum at 6 |
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