1.

Find the maximum and minimum value of the function y=x^3-3x^2+6

Answer»

Dy/dx =3x^2-6x put this equal to 0 ,then find x which is 2
MAX value is max value is 6 and min value is 2 max value is ATTAINS when x=0 which we CANCELLED in dy/dx EQN HOPE This Helps You



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