Find the magnitude of the resultant of forces \( 6 N \) and \( 8 N \)

1.	Find the magnitude of the resultant of forces \( 6 N \) and \( 8 N \) acting at \( 240^{\circ} \) to each other
Answer» The resultant of two vectors P and Q is given by:- \(R^2 = P^2 + Q^2 + 2PQ\cos \theta\) By Using this formula, we get, R² = 6² + 8² + 2(6)(8) cos240° R² = 36 + 64 + (2 × 48 × -1/2) R² = 100 - 48 = 52 R = 2√13 Hence, the magnitude of resultant of forces is 2√13 N.

Find the magnitude of the resultant of forces \( 6 N \) and \( 8 N \) acting at \( 240^{\circ} \) to each other

Answer»

The resultant of two vectors P and Q is given by:-

\(R^2 = P^2 + Q^2 + 2PQ\cos \theta\)

By Using this formula, we get,

R² = 6² + 8² + 2(6)(8) cos240°

R² = 36 + 64 + (2 × 48 × -1/2)

R² = 100 - 48 = 52

R = 2√13

Hence, the magnitude of resultant of forces is 2√13 N.

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Find the magnitude of the resultant of forces \( 6 N \) and \( 8 N \) acting at \( 240^{\circ} \) to each other

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