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Find the magnitude of acceleration due to gravity at height of 10 km from the surface of earth. |
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Answer» Solution :`implies` In equation `g_h=g_e(1-(2H)/R_e),h = 10 KM = 10^(4)m` `Re = 6.4 XX 10^(6) m and g_e=9.8 ms^(-2)` `:. g_(h)=9.8 [1-(2XX10^(4))/(6.4xx10^(6))]` `:. g_h=9.8[1-0.003125]` `:. g_h= 9.8 [0.996875]` `:. g_h=9.769375 ms^(-2)` `:. g_h = 9.8 ms^(-2)` |
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