| 1. |
Find the local maxima of the function,y = (x - 1)^2 (2-x) |
|
Answer» Answer: follow me and msg me and take my answer as the brainliest Step-by-step explanation: MAXIMUM or minimum can be seen by using derivatives. Steps1: First FIND first derivative of the function Step2: Put it equal to zero and find x were first derivative is zero Step3: Now find SECOND derivative Step4: Put x for which first derivative was zero in equation of second derivative Step5: If second derivative is GREATER than zero then function takes minimum value at that x and if second derivative is negative then function will take maximum value at that x. If Second derivative is zero them it means that this is the point of inflection. f ′
(x)=3x 2 −12x+9 Putting this equal to zero, we get f ′
(x)=0 3x 2 −12x+9=0 ⇒(x−1)(x−3)=0 ⇒x=1,3 Now let's see the DOUBLE derivative of this function. f ′′
(x)=6x−12 At x=1 f ′′
(1)=6×1−12=−6 So function will take maximum value at x=1, which is given by f(1)=19 At x=3 f ′′
(3)=6×3−12=6 This is positive at x=3, so function will take a minimum value at x=3. Minimum value is given by f(3)=3 3 −6×3 2 +9×3+15=15 Minimum value of the function is 15 Maximum value of the function is 19 |
|