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Find the length of the tangent drawn from any point on the circle `x^2+y^2+2gx+2fy+c_1=0`to the circle `x^2+y^2+2gx+2fy+c_2=0` |
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Answer» Correct Answer - `sqrt(c_(2)-c_(1))` Let `(x_(1),y_(1))` be any point on the circle `x^(2)+y^(2)+2gx+2fy+c_(1)=0` `:. x_(1)^(2)+y_(1)^(2)+2gx_(1)+2fy_(1)+c_(1)=0` (1) The length of the tangent from `(x_(1),y_(1))` to the circle `x^(2)+y^(2)+2gx+2fy+c_(2)=0` is `sqrt(x_(1)^(2)+y_(1)^(2)+2gx_(1)+2fy_(1)+c_(2))=sqrt(c_(2)-c_(1))` [Using (1)] |
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