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Find the length of the sides of a triangle whose vertices are (3, 4), (2, 1) and (5, -2) |
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Answer» Step-by-step EXPLANATION: √(2-3)^2+(1-4)^2=√1+9=√10 √(5-2)^2+(-2-1)^2=√9+9=3√2 √((5-3)^2+(-2-4)^2=√4+36=2√10 |
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