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Find the length of the common chord of the parabola `x^2=4(x+3)`and the circle `x^2+y^2+4x=0`. |
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Answer» Correct Answer - 4 Solving given equations, we have `-x^(2)-4x=4x+12` `rArr" "x^(2)+8x+12=0` `rArr" "x=-2,(x=-6` is not possible) From equation of parabola, `y^(2)=4(-2+3)=4` `:." "y=pm2`. So, curves intersect at (-2,2) and (-2,-2). So, length of common chord is 4. |
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