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Find the length of simple pendulum which complete 6 oxilation in 30 seconds Take g = 9.8 m/s^2 and pie |
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Answer» tion:Time TAKEN for OSCILLATIONS = 1.8 sFrequency = 6/1.8 Hz= 3.33 HzTime PERIOD = 1/F= [1/3.33] s= 0.3 sLength of Simple Pendulum = Time Period = 2T √l/g= 0.3 = 2*3.14* √l/9.8= 0.3 = 6.28 * √I/9.8= 0.3/6.28 = √I/9.8= (0.3)²/(6.28)² = 1/9.8= [(0.3)² * 9.8] / (6.28)² = |= [0.09*9.8] / 39.43 = |= 0.882/39.43 = |= 0.022 m = |or,= 2.2 cm = 1 |
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