Find the length of a rectangle whose perimeter is 26 cm and the width

1.	Find the length of a rectangle whose perimeter is 26 cm and the width is 4 upon 2 by 3
Answer» Answer: $\huge\sf8=<klux>BREADTH</klux>$ Step-by-step explanation: As we know that - PERIMETER of Rectangle= $\large{\boxed{\sf2(L+B)}}$ Given: Breadth or width is $\sf3\frac{4}{<klux>2</klux>}$ So, According to QUESTION - perimeter = 2(L+B) 26= $\sf 2(L+\frac{10}{2})$ 26= $\sf2L +10$ 26-10= $\sf2L$ = $\sf L=\frac{16}{2}$ = $\sf L=8$ ${\boxed{\sf Verification:-}}$ = $\sf26=2(L+B)$ 26 = (8+ 3+4/2)2 26 = (16+10)2 26 = 26