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Find the length and the breadth of a room which satisfies the equation 2x^2+x-300=0 |
Answer» Answer :12 units Step-by-step explanation :Given quadratic equation, 2x² + x - 300 = 0 It is of the form ax² + bx + c = 0 we KNOW, quadratic term = ax² linear term = bx constant term = c Hence for the given quadratic equation, Quadratic term = 2x² Linear term = x Constant term = -300 Steps to factorize : >> Find the product of quadratic term[ax²] and constant term[bx] = 2x² × (-300) = -600x² >> Find the factors of ''-600x²'' in pairs, (x) (-600x) (-x) (600x) (2x) (-300x) (-2x) (300x) (3x) (-200x) (-3x) (200x) (4x) (-150x) (-4x) (150x) (5x) (-120x) (-5x) (120x) (6x) (-100X) (-6x) (100x) (8x) (-75x) (-8x) (75x) (10x) (-60x) (-10x) (60x) (12x) (-50X) (-12x) (50x) (15x) (-40x) (-15x) (40x) (24x) (-25x) (-24x) (25x) (30x) (-20x) (-30x) (20x)
>> From the above, find the PAIR that adds to get linear term[bx] 25x - 24x = x >> SPLIT x as 25x and -24x 2x² + x - 300 = 0 2x² - 24x + 25x - 300 = 0
>> Find the common factor 2x(x - 12) + 25(x - 12) = 0 (x - 12) (2x + 25) = 0 => x - 12 = 0 ; x = 12 => 2x + 25 = 0 ; x = -25/12 The dimensions of the room can't be negative. Hence, x = 12 Therefore, the length and breadth of the room = 12 units |
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