1.

Find the least value of 3sinx – 4cosx + 7please attach explaination too ​

Answer»

ANSWER:

  • maximum value is = (a2 + b2)
  • while MINIMU value is = – (a2 + b2)
  • maximum value is = (32 + 42) – 7 = 5 –7 = –2.
  • minimum value is = – (32 + 42) – 7 = –5 – 7 = –12.



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