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Find the least number which when divided by8,9 and 12, left a reminder 3 in each case butwhen divided by 7, left no remainder. |
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Answer» LCM of 8, 12 and 16 = 48 So The nos. which when divided by 12,16 and 8 and leave remainder 3 will be a multiple of 48 + 3These nos. are 51 ( 48×1 + 3), 99 (48×2 + 3), 147 ( 48×3 +3)... and so on. The least of them which leaves no remainder when divided by 7 is 147. So the ans. is 147. answer is 147 for this question lcm of 8, 12 and 16=48, remainder 3 multiples 49+3 multiples 49+3=, those numbers of 51, (48+1,+3), 99(48×2+3), 147(48×3+3), which leaves no remainder divided by 7 is 147. |
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