1.

Find the least number which when divided by 9 , 15, 18 leave remainder 5 in each case

Answer»

9 = 3 × 3
15 = 3 × 5
18 = 3 × 8



LCM = 3 × 3 × 5 × 8
=> 9 × 40
=> 360




Required NUMBER is ( 360 + 5 ) = 365



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