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Find the least number which when divided by 15,21,35,42 leaving remainder 7 |
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Answer» Find the least number which when DIVIDED by 15, 27, 35 and 42 LEAVES a remainder of 5 in each case. Let us see the factors of the 4 numbers. 15 = 3 x 5 27 = 3 x 3 x 3 35 = 5 x 7 42 = 2 x 3 x 7 The LCM of the four numbers is: 2 x 3 x 3 x 3 x 5 x 7 = 1890. Next ADD 5 to the number: 1890 + 5 = 1895, which is your answer. Check: 1895/15 = 126 + 5 remainder 1895/27 = 70 + 5 remainder 1895/35 = 54 + 5 remainder 1895/42 = 45 + 5 remainder |
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