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Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case ? |
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Answer» SOLUTION : For this particular SUM we need to find the LCM of the given numbers. The smallest NUMBER which when divided by 12 16 24 and 36 = LCM of 12 16 24 and 36 12 = 2×2×3 16 = 2×2×2×2 24 = 2×2×2×3 36 = 2×2×3×3 LCM = 144 The smallest number which DIVIDES 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.
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