Saved Bookmarks
| 1. |
Find the least number which when divide by 626, 618 and 676 leaves a remainder 3 in eachcase. |
|
Answer» ong>Question :- Find the least number which when divide by 626, 618 and 676 leaves a remainder 3 in each case. ? Solution :- The least required number will be :- LCM of (626, 618 and 676) + 3. Lets first find LCM of given numbers . Prime Factors of 626, 618 and 676 are :- → 626 = 2 * 313 → 618 = 2 * 3 * 103 → 676 = 2 * 2 * 13 * 13 So, → LCM = 2 * 2 * 3 * 13 * 13 * 103 * 313 = 65,380,692 . Therefore, → Required Number = LCM + 3 = 65,380,692 + 3 = 65,380,695 . (Ans.) LEARN more :- find the smallest perfect square number that is divisible by 6 ,7 ,8 and 27 |
|