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Find the least number which after being increased by 2 ia exactly divisible by 8 16 and 45 |
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Answer» Answer: 2 is the minimum NUMBER which when INCREASED by 2 is exactly divisible by 8, 16 and 24. LCM=product of each PRIME factor of highest power. Hence LEAST number which after being increased by 2 is exactly divisible by 8 , 16 and 24 is 46. Step-by-step explanation: Hope it helps you...... |
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