1.

Find the least number that divides 626, 3127 and 15628 leaving remainders 1, 2 and 3.​

Answer»

Answer:

The REQUIRED number is 625

Step-by-step explanation:

626 , 3127 and 15628 leaves remainders 1,2 and 3

So,we have to SUBTRACT the following number with their remainders respectively

(1) 626-1=625

(2) 3127-2=3125

(3) 15628-3=15625

Now, we have to find the HCF of thes following RESULTANT number

1) 625=5×5×5×5

2) 3125=5×5×5×5×5

3) 15625=5×5×5×5×5×5

The HCF = 5×5×5×5

= 625

So, the least number that divides the following number is 625.


Discussion

No Comment Found

Related InterviewSolutions