Find the least number of five digits which on dividing by 4,12,20 and

1.	Find the least number of five digits which on dividing by 4,12,20 and 24 leaves remainder 3 in each case
Answer» Least 5 digit number = 10000. LCM(4,12,20,24) = 120 Dividing 10000 by 120 leaves a remainder 40 , Subtract 40 from 10000 = 9960 So this means 9960 is divisible by 120. 9960 + 120 = 10080. To find the number which leaves remainder 3, we have to add 3 to 10080. 10080 + 3 = 10083.

Find the least number of five digits which on dividing by 4,12,20 and 24 leaves remainder 3 in each case

Answer»

Least 5 digit number = 10000.

LCM(4,12,20,24) = 120

Dividing 10000 by 120 leaves a remainder 40 , Subtract 40 from 10000 = 9960

So this means 9960 is divisible by 120.

9960 + 120 = 10080.

To find the number which leaves remainder 3, we have to add 3 to 10080.

10080 + 3 = 10083.