1.

Find the LCM of `(5!,6!,7!).`

Answer» We have
LCM`(5!,6!,7!) = LCM(5!,6xx5!,7xx6xx5!) `
`=(5!)xx"LCM "(1,6,42)=(5!)xx42 `
`=7xx6xx5! =7!. `


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