Find the last digit of the sum of 1!+2!+........+49!
Answer»
1!+2!+3!......+49!= in between this there is 5! and after that EVERY numbers factorial has unit digit 0... so,1!=1 2!=1*2=2 3!=1*2*3=6 4!=1*2*3*4=24 5!=1*2*3*4*5=120 ....... ......... so, 1+2+6+24+120+720...... unit digit=1+2+6+...4=13 last digit=3