Find the last digit of the product 723 x 813

1.	Find the last digit of the product 723 x 813
Answer» 4 is the right answer. the sequence for 7 exponents is 49 last digit 99x7= 63 last digit 33x7= 21 last digit 17x1= 7 last digit 7so the cycle renews ever 7^4hence for 7^23, there are 5 cycles and 3 remainder, so last digit is 1applying similar logic with 8 we get 4 ,hence 4x1=4

Answer»

4 is the right answer.

the sequence for 7 exponents is 49 last digit 99x7= 63 last digit 33x7= 21 last digit 17x1= 7 last digit 7so the cycle renews ever 7^4hence for 7^23, there are 5 cycles and 3 remainder, so last digit is 1applying similar logic with 8 we get 4 ,hence 4x1=4

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Find the last digit of the product 723 x 813

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