Find the largest number which divides 302 and327 leaving remainder 6 i

1.	Find the largest number which divides 302 and327 leaving remainder 6 in each case.
Answer» ong>Step-by-step EXPLANATION: To FIND the largest number which divides 257 and 328 LEAVING remainder 6 in each case we will first subtract 6 from each number 257–6=251 328–6=322 Now find HCF of 251 and 322 by USING Euclid's DIVISION lemma 322=251×1+71 251=71×3+38 71=38×1+33 38=33×1+5 33=5×6+3 5=3×1+2 3=2×1+1 2=2×1+0 So the HCF is 1. Only 1 can divide both the numbers leaving remainder 6 in each case.

Find the largest number which divides 302 and327 leaving remainder 6 in each case.

Answer»

ong>Step-by-step EXPLANATION:

To FIND the largest number which divides 257 and 328 LEAVING remainder 6 in each case we will first subtract 6 from each number

257–6=251

328–6=322

Now find HCF of 251 and 322 by USING Euclid's DIVISION lemma

322=251×1+71

251=71×3+38

71=38×1+33

38=33×1+5

33=5×6+3

5=3×1+2

3=2×1+1

2=2×1+0

So the HCF is 1.

Only 1 can divide both the numbers leaving remainder 6 in each case.