1.

Find the largest number that will divide 398,436and 542 leaving remainder 7,11and 15 respectively.

Answer»

GIVEN :-

398 , 436 and 542

To Find :-

The largest number

Solution :-

Let’s assume the integer is x

According to the condition given in the question

⇒ XY+7 = 398

⇒  xz+11 = 436

⇒  xk+15 = 542

⇒ xy =391

⇒  xz = 425

⇒  xk = 527

⇒  17 × 23 = 391

⇒  17 × 25 = 425

⇒ 17 × 31 = 527

So, the largest possible integer that will DIVIDE 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.


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