Find the largest number that divides 31 and 99 leaving remainder 5 and

1.	Find the largest number that divides 31 and 99 leaving remainder 5 and 8 respectively . also find lcm of 65 and 117 by prime factorisation method .
Answer» Step-by-step explanation: 31-5 = 26 99-8 = 91 therfore, prime factorisation of 26 = 2 x 13-(1) and 91 = 7 x 13-(2) HCF will be the largest number that divides 31 and 99 to leave remainder 5 and 8 respectively . therefore HCF= 13 -(from 1 and 2 ) HOPE THIS HELPS YOU!!!!

Find the largest number that divides 31 and 99 leaving remainder 5 and 8 respectively . also find lcm of 65 and 117 by prime factorisation method .

Answer»

Step-by-step explanation:

31-5 = 26

99-8 = 91

therfore, prime factorisation of 26 = 2 x 13-(1)

and 91 = 7 x 13-(2)

HCF will be the largest number that divides 31 and 99 to leave remainder 5 and 8 respectively .

therefore HCF= 13 -(from 1 and 2 )

HOPE THIS HELPS YOU!!!!

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Find the largest number that divides 31 and 99 leaving remainder 5 and 8 respectively . also find lcm of 65 and 117 by prime factorisation method .

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