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Find the largest number by which when 270, 675 and 1215 are divided, leave equal remainder in each case.A. 45B. 135C. 270D. 751. D2. B3. C4. A |
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Answer» Correct Answer - Option 2 : B Given: Numbers are 270, 675, 1215 Calculation: Let us assume that the remainder left is m So, numbers that are completely divisible are ⇒ 270 – m, 675 – m, 1215 – m Now subtract the pair ⇒ 675 – m – 270 + m = 405 ----1 ⇒ 1215 – m – 675 + m = 540 ----2 Now find the HCF of 405 and 540 ⇒ 405 = 135 × 3 ⇒ 540 = 135 × 4 HCF of 405 and 540 = 135 ∴ The largest number by which 270, 675 and 1215 are divided, leave the equal remainder in each case is 135 |
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