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Find the largest four-digits number which when divided by 4, 7 and 13leaves a remainder of 3 in each case. |
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Answer» first we need to find the LCM:so the LCM of 4,7 and 13 is 364then we divide 364 by the largest 4 digit no. and that is 9999the remainder we get is 171so 9999-171 =98289828 is perfectly divisible by 364 but we need a remainder of 3 so 9828+3=9831therefore 9831 is the largest no divisible by 4,7 and 13 |
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