1.

Find the inverse Laplace transform for 4s+5/(s-1)^2(s+2)​

Answer»

ong>Answer:

L-¹{ 1/{ (s + 2)² + 1 } } = e^(-2) * sin t.

Step-by-step explanation:

1/( s² + 4s + 5) = 1/{ (s + 2)² + 1 }

As we all KNOW that,

L-¹{ a/(s²+a²) } = sin at

L-¹{ f(s+a) } = e^(-a) * F(s)

So,

L-¹{ 1/{ (s + 2)² + 1 } } = e^(-2) * sin t.

Hope it may help you.:)


Discussion

No Comment Found

Related InterviewSolutions