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find the intercept made by line segment 4x+3y+12 is equal to 0 (answer with steps) |
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Answer» The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis. Therefore,For equation 4x + 3y + 12 = 0Convert this equation to standard formy = - 4x/3 - 4 Hence, Intercept for given equation is - 4 Equation of the line segment is 4 * x + 3 * y + 12 = 0,so,x - intercept,put, y = 0,x = - 3,y - intercept,put x = 0,y = -4,hence,intercept of the given line segment 4 * x + 3 * y + 12 = 0 is ( -3, -4 ). |
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