Find the integrals of tanx×secx – InterviewSolution

1.

Find the integrals of tanx×secx

Answer»

ANSWER: -secx+c

Explanation:

$\int\ {tanxsecx} \, <klux>DX</klux>$

$\int\frac{sinx}{cos^{2}x} \, dx$

SUPPOSE ,cosx=z

-sinx dx =dz

⇒ $-\int\frac{1}{z^2} \, dz$

⇒-{ $-\frac{1}{z}$ }+c

⇒ $\frac{1}{cosx}$ +c

⇒secx+c

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