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Find the inradius of an equilateral triangle of side 10cm. User r = A/s |
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Answer» \(s=\frac{10+10+10}{2}=\frac{30}{2}=15\) \(A=\frac{\sqrt{3}}{4}a^2=\frac{\sqrt{3}}{4}10^2=25\sqrt{3}\) \(r=\frac{A}{s}\) \(=\frac{25\sqrt{3}}{15}=\frac{5}{\sqrt{3}}=2.9\) cm |
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