1.

Find the inradius of an equilateral triangle of side 10cm. User r = A/s

Answer»

\(s=\frac{10+10+10}{2}=\frac{30}{2}=15\)

\(A=\frac{\sqrt{3}}{4}a^2=\frac{\sqrt{3}}{4}10^2=25\sqrt{3}\)

\(r=\frac{A}{s}\)

\(=\frac{25\sqrt{3}}{15}=\frac{5}{\sqrt{3}}=2.9\) cm



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