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Find the incentre of the triangle with vertices `(1, sqrt3), (0, 0)` and `(2, 0)` |
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Answer» Correct Answer - `(1,(1)/(sqrt3))` Here `AB=BC=CA=2` So, it is an equilateral triangle and the incentre coincides with centroid. Therefore, centroid `((0+1+2)/(3),(0+0+sqrt3)/(3))-=(1,(1)/sqrt3)` |
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