1.

Find the (i) lengths of axes, (ii) coordinates of the vertices, (iii) coordinates of the foci, (iv) eccentricity, and (v) length of the latus rectum of the hyperbola. Horizontal Hyperbola:For general form of Hyperbola: x2/a2 – y2/b2 = 1 ……..(1) Vertical Hyperbola:For general form of Hyperbola:y2/a2 – x2/b2 = 1 ……..(2) 3y2 – x2 = 108

Answer»

Divide each side by 108

y2/36 – x2/108 = 1

Which is of the form y2/a2 – x2/b2 = 1

On comparing given equation with (2), we get

a = 6 and b = 6√3

Then,

c2 = a2 + b2

c2 = 36 + 108 = 144

or c = 12

Now,

(i) Lengths of the axes:

Length of Transverse axis = 2a = 12 units

Length of Conjugate axis = 2b = 12√3 units

(ii) Coordinates of the vertices: (0, ±a) = (0, ±6)

(iii) Coordinates of the foci: (0, ±c) = (0, ±12)

(iv) Eccentricity: e = c/a = 2

(v) Length of the latus rectum: 2b2/a = 36 units



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