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Find the (i) lengths of axes, (ii) coordinates of the vertices, (iii) coordinates of the foci, (iv) eccentricity, and (v) length of the latus rectum of the hyperbola. Horizontal Hyperbola:For general form of Hyperbola: x2/a2 – y2/b2 = 1 ……..(1) Vertical Hyperbola:For general form of Hyperbola:y2/a2 – x2/b2 = 1 ……..(2) 3y2 – x2 = 108 |
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Answer» Divide each side by 108 y2/36 – x2/108 = 1 Which is of the form y2/a2 – x2/b2 = 1 On comparing given equation with (2), we get a = 6 and b = 6√3 Then, c2 = a2 + b2 c2 = 36 + 108 = 144 or c = 12 Now, (i) Lengths of the axes: Length of Transverse axis = 2a = 12 units Length of Conjugate axis = 2b = 12√3 units (ii) Coordinates of the vertices: (0, ±a) = (0, ±6) (iii) Coordinates of the foci: (0, ±c) = (0, ±12) (iv) Eccentricity: e = c/a = 2 (v) Length of the latus rectum: 2b2/a = 36 units |
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