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Find the height of the point vertically above theearth's surface at which the acceleration due togravity becomes 1% of its value at the surfacein terms of R. (R is the radius of the earth) |
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Answer» gh=gR^2/(R+h)^2 given gH=g/100 Therefore we have gR^2/(R+h)^2=g/100 or R+h=10R or h=9R |
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