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Find the height of on a object reached in the time taken by 2sec(g=10m/s |
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Answer» ong>GIVEN:- g = a = 10 m/s t = 2 sec s (HEIGHT) = ? explaination:- as wkt, s = ut + 1/2 at^2 .... s = (0) 2 + 1/2 (10) (2)^2 hence by equating the above SUM we will get s (height) = 20 meters. HOPE IT HELP'S YOU.. |
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