Find the height of a cylindrical box with volume 13400 cm3 and area of

1.	Find the height of a cylindrical box with volume 13400 cm3 and area of the base 670 cm2
Answer» $\begin{gathered}\begin{gathered}\bf Given - \begin{cases} &\sf{V_{(Cylinder)} = 13400 \: {cm}^{3} } \\ &\sf{base \: area \: = 670 {cm}^{<klux>2</klux>} } \end{cases}\end{gathered}\end{gathered}$ $\begin{gathered}\begin{gathered}\bf To \: Find - \begin{cases} &\sf{height \: of \: cylinder} \end{cases}\end{gathered}\end{gathered}$ $\begin{gathered}\Large{\bold{\pink{\underline{Formula \: Used \::}}}} \end{gathered}$ $\large{ \boxed{ \boxed{ \green{\tt \: V_{(Cylinder)} = base \: area \: \times height}}}}$ $\large\underline\purple{\bold{Solution :- }}$ ☆ Using Formula $\tt \longrightarrow \: V_{(Cylinder)} = base \: area \: \times height$ $\tt \longrightarrow \: 13700 = 670 \times height$ $\tt \longrightarrow \: height \: = \dfrac{13400}{670}$ $\tt\implies \: \boxed{ \red{ \bf \: height \: = \: 20 \: cm}}$ ─━─━─━─━─━─━─━─━─━─━─━─━─ ● More information :- Perimeter of rectangle = 2(length× BREADTH) DIAGONAL of rectangle = √(length ²+breadth ²) Area of square = side² Perimeter of square = 4× side Volume of cylinder = πr²h T.S.A of cylinder = 2πrh + 2πr² Volume of cone = ⅓ πr²h C.S.A of cone = πrl T.S.A of cone = πrl + πr² Volume of cuboid = l × b × h C.S.A of cuboid = 2(l + b)h T.S.A of cuboid = 2(lb + bh + lh) C.S.A of cube = 4a² T.S.A of cube = 6a² Volume of cube = a³ Volume of sphere = 4/3πr³ Surface area of sphere = 4πr² Volume of HEMISPHERE = ⅔ πr³ C.S.A of hemisphere = 2πr² T.S.A of hemisphere = 3πr²

Find the height of a cylindrical box with volume 13400 cm3 and area of the base 670 cm2

Answer»

$\begin{gathered}\begin{gathered}\bf Given - \begin{cases} &\sf{V_{(Cylinder)} = 13400 \: {cm}^{3} } \\ &\sf{base \: area \: = 670 {cm}^{<klux>2</klux>} } \end{cases}\end{gathered}\end{gathered}$