Find the height of a cuboid with length 10m , breadth 5m , volume 62.5

1.	Find the height of a cuboid with length 10m , breadth 5m , volume 62.5m^3
Answer» AnswEr-: $\boxed {\mathrm { Height\:of\:Cuboid = 1.25 m}}$ Explanation-: $\sf{Given-:}$ The LENGTH of Cuboid is 10 m The Breadth of Cuboid is 5 m The VOLUME of Cuboid is 62.5m³ $\sf{To\:Find-:}$ The height of Cuboid. $\dag{\underline {\mathrm{Solution \:of\:Question \:-: }}}$ $\underbrace{\mathrm{Understanding \:the\:Concept-:}}$ We have to Find the Height of Cuboid when Length, Breadth and Volume of cuboid is given or known . For this we have to put the known or Given Values in Formula for Volume of Cuboid then , We can get the height of the Cuboid,. As We KNOW that -: $\underline{\boxed{\mathrm {\dag{\red{ Volume _{(Cuboid)}-: Length \times Breadth\times Height \:or\:lbh\:cube.units}}}}}$ *Here* , The length of Cuboid is 10 m The Breadth of Cuboid is 5 m The Volume of Cuboid is 62.5m³ The Height of Cuboid is ?? Now , By Putting Known or Given Values in the Formula for Given of Cuboid-: $\longrightarrow {\mathrm {10 \times 5 \times Height = 62.5 m^{3}}}$ $\longrightarrow {\mathrm { 50 \times Height = 62.5 m^{3}}}$ $\longrightarrow {\mathrm {Height = \dfrac{62.5}{50} }}$ $\longrightarrow {\mathrm {Height = \dfrac{\cancel {62.5}}{\cancel {50}} }}$ $\longrightarrow {\mathrm { Height = 1.25 m}}$ *Hence* , $\boxed {\mathrm { Height\:of\:Cuboid = 1.25 m}}$ ____________________________________ $\huge{\dag{\mathrm{Verification-:}}}$ $\underline{\boxed{\mathrm {\dag{\red{ Volume _{(Cuboid)}-: Length \times Breadth\times Height \:or\:lbh\:sq.units}}}}}$ *Here ,* The length of Cuboid is 10 m The Breadth of Cuboid is 5 m The Volume of Cuboid is 62.5m³ The Height of Cuboid is 1.25 m Now , By Putting Known or Given Values in the Formula for Given of Cuboid-: $\longrightarrow {\mathrm {10 \times 5 \times 1.25 = 62.5 m^{3}}}$ $\longrightarrow {\mathrm {50 \times 1.25 = 62.5 m^{3}}}$ $\longrightarrow {\mathrm {62.5m^{3} = 62.5 m^{3}}}$ Therefore, $\longrightarrow {\mathrm {LHS= RHS}}$ $\longrightarrow {\mathrm {Hence\:Verified!}}$ ________________________♡________________________