1.

Find the height and LSA of a cylinder if it's redius is 28 and TSA is 5805m^2​

Answer»

Given :-

● Total surface area of cylindrical = 5805m^2

● Radius of the cylinder = 28m

Solution :-

Here ,

Radius of the cylinder = 28m

TSA of cylinder = 5805m^2

The VALUE of π = 22/7

As we know that,

TSA of cylinder = 2πr( r + h)

PUT the required values in the given formula,

5805 = 2 * 22/7 * 28 ( 28 + h )

5805 = 2 * 22 * 4 ( 28 + h )

5805 = 44 * 4 * ( 28 + h )

5805 = 176 ( 28 + h )

5805 = 4928 + 176 h

5805 - 4928 = 176h

877 = 176h

h = 4.98m

[you can take approx value also that is 5]

Now,

LSA of Cylinder = 2πrh

Put the required values in the formula ,

LSA of Cylinder = 2 * 22/7 * 28 * 4.98

LSA of Cylinder = 2 * 22 * 4 * 4.98

LSA of Cylinder = 44 * 4 * 4.98

LSA of Cylinder = 176 * 4.98

LSA of Cylinder = 876.48m^2

Hence, The Lateral surface area of cylinder is 876.48m^2 .



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