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Find the height and LSA of a cylinder if it's redius is 28 and TSA is 5805m^2 |
Answer» Given :-● Total surface area of cylindrical = 5805m^2 ● Radius of the cylinder = 28m Solution :-Here , Radius of the cylinder = 28m TSA of cylinder = 5805m^2 The VALUE of π = 22/7 As we know that,TSA of cylinder = 2πr( r + h) PUT the required values in the given formula,5805 = 2 * 22/7 * 28 ( 28 + h ) 5805 = 2 * 22 * 4 ( 28 + h ) 5805 = 44 * 4 * ( 28 + h ) 5805 = 176 ( 28 + h ) 5805 = 4928 + 176 h 5805 - 4928 = 176h 877 = 176h h = 4.98m [you can take approx value also that is 5] Now,LSA of Cylinder = 2πrh Put the required values in the formula ,LSA of Cylinder = 2 * 22/7 * 28 * 4.98 LSA of Cylinder = 2 * 22 * 4 * 4.98 LSA of Cylinder = 44 * 4 * 4.98 LSA of Cylinder = 176 * 4.98 LSA of Cylinder = 876.48m^2 Hence, The Lateral surface area of cylinder is 876.48m^2
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