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find the height above the surface of earth where the value of acceleration due to gravity falls to 1% at the surface of the earth |
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Answer» that gravity at any height is GIVEN as;G’ = g (1 - 2h/R) —[1]DECREASE by 1% implies that g’ = 99/100gSubstitute In 1,we get99/100g = g (1 - 2h/R)99/100 = 1 - 2h/R2h/R = 1 - 99/1002h/R = 1/100h = R/200h = 6400/200 (R = 6400KM)H = 32KM From surface of EARTH |
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