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Find the HCF of 1794 , 2346 , 4761 by continued division method. |
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Answer» first consider 1794,2346 => 1794)2346(1 1794 552)1794(3 1652 142)552(3 426 126)142(1 126 16)126(7 112 14)16(1 14 2)14(7 14 0 so, HCF of 1794, 2346 is 2 now we should find the HCF of 2,4761 => 2)4761(2380 4760 1 )2(2 2 0 so, HCF of 1794,2346,4761 was 1
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