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Find the greatest number will dividual 615 and a 963 leaving the six in each case |
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Answer» Step-by-step explanation: The required GREATEST number be the H. C. F of ( 615 - 6 ) and ( 963 - 6 ) so we will find the H. C. F of 609 and 957 GIVEN numbers are 957 and 609 clearly 957 > 609 . Therefore it is the H. C. F of 609 and 957. The remainder at this step is zero. so the divisor at this stage I.e 87 is the H. C. F of 609 and 957 Therefore 87 is the required greatest number that will divide 615 and 963 leaving 6 in each case Hope it will help you |
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